Calculate the total positive (or negative) charge on a 3.11 g copper penny. Given Avogadro's number `=6.023xx10^(23)g mol^(-1),`, and atomic mass=63.5.

Options

A. `1.37xx10^(7) C`
B. `2.5xx10^(5) C`
C. `1.37xx10^(5) C`
D. `2.5xx10^(7) C`

Answer

C

Explanation

The number of atoms in the penny is
`[(6.02xx10^(23))/(63.5)]3.11=0.295xx10^(23)`
since each copper atom contains 29 protons (and 29 electrons),the total number of positive (or negative) charge in the penny is `n=29(0.295xx10^(23))=8.56xx10^(23)`
Total charge (positive or negative)on the penny is
`q="ne"=(8.56xx10^(23))(1.6xx10^(-19)C)`
`=1.37xx10^(5) C`