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A charged particle of radius 5xx10^(-7)m...

A charged particle of radius `5xx10^(-7)m` is located in a horizontal electric field of intensity `6.28xx10^(5)Vm^(-1)`. The surrounding medium has the coeffiecient of viscosity `eta=1.6xx10^(5)Nsm^(-2)`. The particle starts moving under the effect of electric field and finally attains a uniform horizontal speed of `0.02 ms^(-1)`. Find the number of electrons on it. Assume gravity free space.

Text Solution

Verified by Experts

The correct Answer is:
`3xx10^(11)`
`qE= 6 pi eta rv`
or `NeE= 6 pi eta rv` or `N= 6 pi eta rv//eE`
or ` N=(6 pixx1.6xx10^(5)xx5xx10^(-7)xx0.02)/(1.6xx10^(-19)xx6.28xx10^(5))=3xx10^(11)`.
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