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A long, straight wire is surrounded by a...

A long, straight wire is surrounded by a hollow metal cylinder whose axis coincides with that of the wire. The wire has a charge per unit length of `lambda`, and the cylinder has a net charge per unit length of `2lambda`. From this information, use Gauss's law to find (i) the charge per unit length on the inner and outer surfaces of the cylinder and (ii) the electric field outside the cylinder, a distance r from the axis.

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To solve the problem step by step, we will use Gauss's law to find the charge per unit length on the inner and outer surfaces of the hollow metal cylinder and the electric field outside the cylinder. ### Step 1: Understanding the Setup We have a long straight wire with a charge per unit length of \( \lambda \) and a hollow metal cylinder with a net charge per unit length of \( 2\lambda \). The wire is placed along the axis of the cylinder. ### Step 2: Charge Distribution on the Cylinder 1. **Inner Surface Charge**: - The electric field inside a conductor in electrostatic equilibrium is zero. Therefore, the charge on the inner surface of the cylinder must be such that it cancels the electric field due to the wire. ...
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Knowledge Check

  • The charge deposited per unit length of cylinder is called as

    A
    linear charge density
    B
    surface charge density
    C
    charge density
    D
    all of these
  • The electric field at a distance r from a long wire having charge per unit length lambda is

    A
    `k((lambda)/(r^(2)))`
    B
    `k((lambda)/(r))`
    C
    `k((lambda)/(2r))`
    D
    `k((2lambda)/(r))`
  • The charge per unit length of the four quadrant of the ring is 2 lambda, -2lambda, lambda and -lambda respectively. The electric field at the centre is:

    A
    `(-lambda)/(2piepsilon_(0)R)hat(i)`
    B
    `lambda/(2pi epsilon_(0)R) hat(j)`
    C
    `(sqrt(2)lambda)/(4 pi epsilon_(0)R) hat(i)`
    D
    None
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