figure shows the field produced by two point charges +q and -q of equal magnitude but opposite signs (an electric dipole). Find the electric flux through each of the closed surfaces A,B,C, and D.

Explanation

Flux through closed surface A,
`phi_A = Q_(in)/epsilon_0 = q/epsilon_0`
Flux through closed surface B,
`Q_B = -q/epsilon_0`
Flux through surface C,
`Q_C = (q-q)/epsilon_0 = 0 and Q_D = Q_(in)/epsilon_0 = 0` .