Charge on an originally uncharged conductor is separated by holding a positively charged rod very closely nearby, as shown in figure. Assume that the induced negative charge on the conductor is equal to the positive charge q on the rod. Then the flux through surface `S_1` is

Options

A. zero
B. `q//epsilon_0`
C. `-q//epsilon_0`
D. none of these

Answer

B

Explanation

b. Net charge on the conductor will be zero. So, net charge inside
`S_1` will be the charge on the rod. Hence, flux through `S_1` is `q//epsilon_0`.