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A 5.0muF capacitor is charged to 12V. Th...

A `5.0muF` capacitor is charged to `12V`. The positive plate of this capacitor is now connected to the negative terminal of a `12V`battery and vice versa . Calculate the heat developed in the connecting wires.

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From figure, net charge flow through battery is `Q_("final")-Q_("initial")=epsilonC-(-epsilonC)=2epsilonC`
Thus, work done by battery `(W)` is `QxxV=2epsilonC xx epsilon = 2 epsilon^(2)C` or heat produced is `2epsilon^(2)C`
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CENGAGE PHYSICS-CAPACITOR AND CAPACITANCE-Exercise 4.2
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