A capacitor of capacitance `C_1 = 1.0muF` charged upto a voltage `V = 110 V` is connected in parallel to the terminals of a circuit consisting of two uncharged capacitors connected in series and possessing the capacitance `C_2 = 2.0 muF` and `C_3 = 3.0muF`. What charge will flow through the connecting wires?

Options

A. `40 muC`
B. `50 muC`
C. `60 muC`
D. `110 muC`

Answer

C

Explanation

Initial charge on `C_(1)` is `Q_(1)=C_(1) V=110 muC`
Let `x` charge flow through wires.
`(Q_(1)x)/C_(1)=x/C_(eq)`
where `C_(eq)=(C_(2)xxC_(3))/(C_(2)+C_(3))`
Solve to get `x=60 muC`.