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Two identical parallel plate capacitors ...

Two identical parallel plate capacitors are connected in series and then joined in series will a batter of `100 V`. `A` slab of dielectric constant `K=3` is inserted between the plates of the first capacitor. Then, the potential difference across the capacitor will be, respectively.

A

`25 V,75 V`

B

`75 V,25 V`

C

`20 V,80V`

D

`50 V, 50 V`

Text Solution

Verified by Experts

The correct Answer is:
A
`V_(1)=(Cxx100)/(3C+C)=25 V, V_(2)=100-25=75 V`.
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