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A 5.80 muF parallel-plate air capacitor ...

A `5.80 muF` parallel-plate air capacitor has a plate separation of `5.00 mm` and is charged to a potential difference of `400 V`. Calculate the energy density in the region between the plates, in `J/m^3`

A

`0.113`

B

`0.117`

C

`0.152`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`A=90 cm^(2),d=2 mm`
`E=V/d,V400V`
`u=1/2epsilon_(0)E^(2)=1/2=1/2epsilon_(0)(V/d)^(2)`
`=1/2(8.85x10^(-12))((400)/(2xx10^(-3)))^(2) =0.177 Jm^(-3)`.
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