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A dielectric slab fills the lower as sho...

A dielectric slab fills the lower as shown in. (Take plate area as `A`).
.

A

Equivalent is `(epsilon_(0)A//2d)(1+K)`.

B

The net charge of the lower half of the left hand plate is `1//K` times the charge on the upper half the plate.

C

Net charge on the lower and upper halves of the left hand plate are different.

D

Net charge on the lower half oof thenleft hand plate is `(Kepsilon_(0)A)/(2d)xxV`.

Text Solution

Verified by Experts

The correct Answer is:
A, C, D
This system can be considered as two capacitors in parallel, with
`C_(1)=(epsilon_(0)A)/(2d)` and `C_(2)=(Kepsilon_(0)A)/(2d)`
`C_(1)` is due to spper half of two plates, while `C_(2)` is due to lower half. As potential difference across two capacitors is the same, charges would be different as capcitors are differnt.
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