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In the circuit diagram shown in Fi, ....

In the circuit diagram shown in Fi,
.

A

the charge on `2 muF` capacitor is `8 muC`

B

the charge on each `6 muF` capacitor is `72 muC`

C

the pottential drop across `1 muF` capacitor is `4 V`.

D

the potential drop across `3 muF` is 4 V`

Text Solution

Verified by Experts

The correct Answer is:
A, C, D

Capacitors `1 muF, 2 muF, And 3 muF` are in parallel, and their total capacitance is `6 muF` Thus, we have three capcitors in series, each of capacitance `6 mu F` across the `12 V` power supply. So potential drop across each is `12/3=4 V`. So options `(a)` and `(b)` are correct. charge on `2 muF` capacitor is `CV=22xx4=8 muC`. So option `(c)` is correct.
Charge on ` 6muF` capacitor is `6xx10^(-6)xx=24 muC`. So option `(d)` is wrong.
Thus, correct options are `(a), (b)`, and `(c)`.
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