Two capacitors of capacity `6 muF` and `3 muF` are charge `100 V` and `50 V` separately and connected as shown in (Fig.4.201.) Now all the three switches `S_(1),S_(2)`, and `S_(3)` are closed.

Charge on the `6 muF` capacitor in steady state will be.

Options

A. `400 muC`
B. `700 muC`
C. `800 muC`
D. `250 muC`

Answer

B

Explanation

(1) `((150-x))/3+((600-x))/6-200=0`
`x=-100 muC`
Hence, final charge on `6 muF` Capacitor is
`q_(1)=700 muC` and charge on `3 muF` is `q_(2)=250 muC`
`q_(1)=(600-x) q_(2)=(150-x)`
. Plates `2` and `3` and plates `1` and `4` form isolated system.
Hence `q_(1)=q_(2)=q_(3)=x=-100 muC`.