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A given wire is stretched to double its ...

A given wire is stretched to double its length. How will its resistance change ?

A

R

B

2R

C

3R

D

4R

Text Solution

Verified by Experts

The correct Answer is:
D
We know that
`R = (rhol)/(A)`
Let new resistance be
`R' = (rhol)/(A')`
By conservation principle, volume of the wire remains
costant. So `A'l' = Al, if l' = 2l, then A' = A/2. Thus`
`R' = (rhoxx2l)/(A//2) = 4 or (rhol)/(A) =4R`
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