Consider a conductor of length 40 cm where a potential difference of 10V is maintained between the ends of the conductor. Find the mobility of the electrons provided the drift velocity of the electrons is `5xx10^(-6) ms^(-1)`

Explanation

Given `L = 40 cm, V = 10V, nu_d = 5xx10^(-6) ms^(-1).`
To find the electron mobility, we need the value of the
electric field, which can be obtained using the following
formula:
`E = (V)/(I) or E = (10)/(0.4) = 25Vm^(-1)`
Also the formula used for electron mobility is
`mu = (nu_d)/(E) = (5xx10^(-6))/(25) = (1)/(5)xx10^(-6)`
`=0.2xx10^(-6) = 2xx10^(-7) m^2 V^(-1) s^(-1)`