Home
Class 12
PHYSICS
In the circuit shown in E, F, G, and H a...

In the circuit shown in E, F, G, and H are cells of emf 2,1,3 and 1 V, respectively. The resistances `2Omega, 1Omega, 3Omega and 1Omega` are their respectivle internal resistances.

i. Find the potential difference between B and D.
(ii) Calculate the potential differences across the terminals of each of the cells G and H.

Text Solution

Verified by Experts

The circuit with the currents shown is redrawn in Applying the loop law to BADB, we get

`-2i_1+2 -1 -1i_1 - 2(i_1-i_2) = 0` or `- 5i_1 +2i_2 = -1 (i)`
Applying the same law to loop DCBD, we get
`-3 - 3i_2 - 3i_2 +1+(i_1 - i_2) = 0` or `2i_1 - 6i_2 = 2 (ii)`
From Eqs. (i) and (ii) we get
`i_1 = (1)/(12)A, i_2 = -(4)/(13)A`
`:. i_1 - i_2 = (5)/(13) A`
i. `V_D - V_B = (2Omega)((5)/(13))A = (10)/(13)V`
ii. Potential differences across the cell G is
`V_D - V_C = 3 +3i_2 = 3+3(-4//13) = 2713V`
Potential difference across the cell H is
`V_B -V_C =1 -i_2 = 1+ 4//13 = 17//13V.`
`(:. V = E + ir)`
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC CURRENT AND CIRCUIT

    CENGAGE PHYSICS|Exercise Solved Examples|12 Videos

  • ELECTRIC CURRENT AND CIRCUIT

    CENGAGE PHYSICS|Exercise Exercise 5.1|28 Videos

  • ELECTRIC CURRENT & CIRCUITS

    CENGAGE PHYSICS|Exercise Kirchhoff s law and simple circuits|15 Videos

  • ELECTRIC FLUX AND GAUSS LAW

    CENGAGE PHYSICS|Exercise MCQ s|38 Videos

Similar Questions

Explore conceptually related problems

In the circuit shown in figure E,F, G and H are cell of emf 2,1,3, and 1 V respectively. The resistances 2,1,3 and 1(Omega)are their respective internal resistance .Calculate (a)the potential difference between B and D and (b) the potential differences across the terminals of each of each of the cells G and H.

In the circuit shown E, F, G and H are cells of emf 2V, 1V, 3V and 1V respectively and their internal resistance are 2Omega, 1Omega, 3Omega and 1Omega respectively.

In the circuit shown in figure-3.159 cells E,F,G and H are of EMF 2V, 1V,3V and 1V respevitly and their internal resitance are 2Omega,1Omega,3Omega and 1Omega respectively Calculate (a) The potential difference between points B and D (d) The potential difference across the terminals of the cell G and H.

In the circuit E,F,G,H are cell of emf 2,1,3 and 1 Omega respectively .The potential difference across the terminal of each of the cell G and H are

In the circuit shown in figure. The cells E,F,G and H have e.m.f's 2,1,3 and 1 V and internal resistance 2,1,3 and 1Omega respectively. Find the potential differences between points B and D, and across the terminals of the cells G and H.

The internal resistances of two cells shown are 0.1Omega and 0.3 Omega . If R = 0.2 Omega , its potential difference across the cell

A cell has emf of 2.2 V, when connected to a resistance of 5 Omega , the potential difference between the terminals of the cell becomes 2.1 V, the internal resistance for the cell is

In the shown circuit the following battery is of emf 4V and internal resistance 8 Omega . Find the potential difference between points x and y as shown in the circuit.

Four resistances 40Omega, 60Omega, 90Omega and 100Omega make the arms of a quadrilateral ABCD. Across AC is a battery of emf 40 V and internal resistance negligible. The potential difference across BD in V is ________.

The circuit in Fig. shows two cells connected in opposition to each other. Cell E_(1) is of emf 6V and internal resistance 2Omega, the cell E_(2) is of emf 4 V sand internal resistance 8omega . Find the potential difference between the points A and B .