Home
Class 12
PHYSICS
In a mixed grouping of identical cells, ...

In a mixed grouping of identical cells, five rows are connected in parallel and each row contains 10 cells. This combination sends a current I through an external resistance of `20Omega.` if the emf and internal resistance of each cell is 1.5 V and `1 Omega,` respectively then find the value of I.

A

5/22 A

B

15/22 A

C

3/7 A

D

5/9 A

Text Solution

Verified by Experts

The correct Answer is:
B

The number of cells in a row is n =10, and the number of such rows is m =5.
`I = (nE)/((R +(nr)/(m))) = (10xx1.5)/((20 + (10xx1)/(5))) = (15)/(22) = 0.68`
Promotional Banner

Topper's Solved these Questions

  • ELECTRIC CURRENT AND CIRCUIT

    CENGAGE PHYSICS|Exercise Solved Examples|12 Videos
  • ELECTRIC CURRENT AND CIRCUIT

    CENGAGE PHYSICS|Exercise Exercise 5.1|28 Videos
  • ELECTRIC CURRENT & CIRCUITS

    CENGAGE PHYSICS|Exercise Kirchhoff s law and simple circuits|15 Videos
  • ELECTRIC FLUX AND GAUSS LAW

    CENGAGE PHYSICS|Exercise MCQ s|38 Videos

Similar Questions

Explore conceptually related problems

Two similar cells, whether joined in series or in parallel, have the same current through an external resistance of 2Omega . The internal resistance of each cell is :

Two identical cells whether connected in parallel or in series gives the same current, when connected to an external resistance 1.5Omega . Find the value of internal resistance of each cell.

The n rows each containinig m cells in series are joined parallel. Maximum current is taken from this combination across jan external resistance of 3 Omega resistance. If the total number of cells used are 24 and internal resistance of each cell is 0.5 Omega then

A battery of 6 V internal resistance 0.5 Omega is joined in parallel with another of 10 V and internal resistnace 1 Omega . The combination sends a current through an external resistance of 12 Omega . Find the current through each battery.

Two identical cells , whether joined together in series or in parallel give the same current, when connected to external resistance of 1 Omega . Find the internal resistance of each cell.