Find the minimum number of k cells required to produce a current of 1.5A through a resistance of `30Omega.` Given that the emf of each cell is 1.5V and the internal resistance is `1Omega`

Explanation

`nm = ? , 30 = (nxx1)/(m) o rln = 30m`,
`1.5 = (nxx1.5)/(30+ (n)/(m))`
On solving we get n 60, m=2, total number nof batteries =
mm = 120.