Find the current in each resistor of the circuit shown in fig
a. Current through resistance of `6 Omega is ………..`
b. Current through resistance of `3 Omega is ………..`
c. Current through resistance of `2 Omega is ………..`
d. Current through resistance of `5 Omega is ………..`

Explanation

Applying Kirchhoff's current law, we get

At node `V, (26-V)/(6) +(8-V)/(3) = (V-0)/(2) or V =7V`
Current through the ` 6Omega` resistor is `I_6 = (26 - 7)/(6) = (19)/(6)A`
Current through the ` 3Omega` resistor is `I_3 =(8-7)/(3) = (1)/(3)A`
Current through the ` 2Omega` resistor is `I_2 = (7)/(2)A`
Current through the `5Omega` resistor is `I_6 = (26)/(5)A`