Find the current in each wire.

Explanation

Let potential at point B be
0. The potentials at other
points are mentioned. So
potentia at E is not known
numerically. Let potential
at E be x.
Now applying Kirchhoff's
current law at junciton E
(this can be applied at any
other jucntion also), we get
`(x-10)/(1) +(x-30)/(2) +(x+14)/(2) = 0`
or `4x = 36 or x =9`
Current in `EF =(10 -9)/(1) =1` A (form F to E)
Current in `BE = (30-9)/(2) = 10.5` A (form B ot E)
Current in `DE = (9-(-14))/(2) = 11.5` A (from E to D)