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The plates of a 50(mu)F capacitor charge...

The plates of a `50(mu)F` capacitor charged to `400(mu)C` are connected through a resistance of `1.0k(Omega)`. Find the charge remaining on the capacitor 1s after the connection is made.

A

`8.2xx10^(-7)muC`

B

`8.2xx10^(-2)muC`

C

`8.2xx10^(-5)muC`

D

`8.2xx10^(-8)muC`

Text Solution

Verified by Experts

The correct Answer is:
A
`q_(1) = 400 muC, C = 50muF`
`R = 1000Omega, tau = RC = 50xx10^(10)xx1000= 5xx10^(-2)s`
`q = q_(0)e^(-t//tau) = 400e^((1)/(5xx10^(-2))) = (400)/(e^(+20))muC`
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