Shows a Wheatstone bridge circuit. Which of the following correctly showsk the currents `I_1, I_2 and I_3` in the decreasing order of magnitude?

Options

A. `I_1, I_2, I_3`
B. `I_2, I_3, I_1`
C. `I_2, I_1, I_3`
D. `I_3, I_2, I_1`

Answer

C

Explanation

Let R be the rersistance of the wire and let R' be the resistance
of the wire. Energy released in t seconds is `(3V^2)Rxxt.`
R' = 2R (as length in twice)
Therefore, energy released in t seconds is `((NV^2))/(2R)xxt`
But `Q = mc DeltaT`
`:. Q' = ((N^2V^2))/(2R)xxt`
`:. mc Delta T = ((9V^(2)))/(R )xxt`
Applying `Q' = m' c Delta T,`
`2mc Delta T = ((N^2V^2))/(2R)xxt`
Dividing Eq. (ii) by Eq. (i)j we get
`(mc Delta T)/(2mc Delta T) = (9V^2 xxt //R)/(N^2V^2 t/2R)`
`:. (1)/(2) = (9xx2)/(N^2) or N = 6`