In the given circuit, with steady current, the potential drop across the capacitor must be

Options

A. V
B. `V//2`
C. `V//3`
D. `2V//3`

Answer

C

Explanation

V = E -ir. When I = 0, the potential reading is 2V. Hence emf
is 2 V. When V = 0, I = 5A. Thisk gives `r = 0.4 Omega.`