In the circuit shwon in fig. switch S is closed at time t = 0. Let `I_1 and I_2` be the currents at any finite time t, then the ratio `I_1// I_2`

Options

A. is constant
B. increases with time
C. decreases with time
D. first increases, then decreases

Answer

C

Explanation

`I = I_(0)e^(-t//RC) or (I_(0))/(2) = I_(0)e^(-t//RC) or t = RC in 2`
or `10^(-6) xx In4 =(2+r)xx0.5xx10^(-6)In 2`
Solving to get `r = 2 Omega`