Consider the circuit shown in fig.

Current through `R_2` is zero if `R_4 = 2Omega and R_3 = 4 Omega` in this case

Options

A. Current through `R_3 = 2.5A`
B. Current through `R_4 = 3A`
C. both (a) and (b) are correct
D. both (a) and (b) are wrong

Answer

D

Explanation

`15 - IR_3 -IR_4 = 0`
Given `R_3 = 4Omega and R_4 =2Omega`
`I = 2.5 A` through `R_3 and R_4`
`-10-IR_1 +5 = 0`
or `I = (5)/(R_1) =2.5A`
`15 - 6I - 5 -2I +10 = 0`
or `I = (20)/(8) =2.5A`