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Consider the circuit shown in fig. ...

Consider the circuit shown in fig.

Assuming `R_1 = 2Omega,` current passing through resistance `R_1` is

A

2A

B

2.5A

C

3.5A

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
`15 - IR_3 -IR_4 = 0`
Given `R_3 = 4Omega and R_4 =2Omega`
`I = 2.5 A` through `R_3 and R_4`
`-10-IR_1 +5 = 0`
or `I = (5)/(R_1) =2.5A`
`15 - 6I - 5 -2I +10 = 0`
or `I = (20)/(8) =2.5A`
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