Find the potential difference (inV) between points A and B shown in the circuit.

Answer

6

Explanation

9V and `16 Omega` can be ignored because potential difference between A and c is fixed, which is 4V. The circuit can be drawn as follows : ,
Equivalent emf is `e = (Sigma(E//r))/(Sigma(1//r)) = (10//2 +4//2)/(1//2 + 1//2) = 7V`
Equivalent internal resistance is `r_0 = (1)/(Simga(1//r) = (1)/(1//2 +1//2) = 1Omega`
Now `V_(AB)= (7)/((6+1)) xx6 = 6V`