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In an experiment with a potentiometer, t...

In an experiment with a potentiometer, the null point is
obtained at a distance of `60 cm` along the wire from the
common terminal with a leclanche cell. When a shunt
resistance of `1 Omega` is connected across the cell, the null
point shifts to a distance of `30 cm` from the common
terminal. what is the internal resistance of the cell?

Text Solution

Verified by Experts

Internal resistance of the cell is given by
`r = R((l_(1) - l_(2))/(l_(2)))`
`= 1 xx (60 - 30)/(30) Omega = 1 Omega`
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