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In the circuit shows in Fig. 6.41, the r...

In the circuit shows in Fig. `6.41`, the reading of the ammeter is (assume internal resistance of the battery be to zero)

A

`(40)/(29)A`

B

`(10)/(9) A`

C

`(5)/(3) A`

D

`2 A`

Text Solution

Verified by Experts

The correct Answer is:
D
Voltage across `5 Omega` is `10 V`. Therefore,
`I = (10)/(5) A = 2A`
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