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A galvanometer has a resistance of 3663O...

A galvanometer has a resistance of `3663Omega`. A shunt `S` is connected across it such that (`1//34`) of the total current passes through the galvanometer. Then the value of the shunt is

A

`3663 Omega`

B

`111 Omega`

C

`107.7 Omega`

D

`3555.3 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
`(I_(g))/(I) = (S)/(S + G)` or `(1)/(34) = (S)/(S + G)`
`:. S = (G//33) = (3663//33) = 107.7 Omega`
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