In the circuit shown in Fig. 7.45,

Options

A. Power supplied by the battery is `200 W`
B. current flowing in the circuit is `5 A`
C. Potential difference across the `4 Omega` resistance is equal to the potential difference across the `6 Omega` resistance
D. current in wire `AB` is zero

Answer

A, C

Explanation

Resistors ` 4 Omega and 6 Omega` are short - circuited. Therefore, no current will flow through these resistances. Current passing through the battery is `I = (20//2) = 10 A`. This is also the current passing in wire `AB from B to A`. Power supplied by the battery is `P = EI = (20)(10) = 200 W`. potential difference across the `4 Omega` resistance is equal to the potential difference across the `6 Omega` resistance.