Consider the situation shown in figure. We find electric field E at point P using Gauss's law and it comes out to be `E = sigma//epsilon_0`. This electric field is due to

Options

A. all the amount of charges present on both the plates
B. all the charges present on positive plate only
C. positive charge present only inside the Gaussian surface.
D. positive charge present inside the Gaussian surface plus equal magnitude of negative charge present on negatice plate in front of Gaussian surface.

Answer

A

Explanation

According to gauss's law, electric field at any point on gaussian surface is due to all the charges present inside or outside.