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A 16 muF capacitor , initially charged t...

A `16 muF` capacitor , initially charged to 5 V, is started charging at t=0 by a source at the rate of `40 tmuCs^(-1)`. How long will it take to raise its potential to 10 V?

A

1 s

B

2 s

C

3 s

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`q_(i)=CV_(i)=16xx5=80muC,q_(f)=CV_(f)=16xx10=160muC`
given `(dq)/(dt)=40timpliesint_(q_(i))^(q_(f))dq=int_(0)^(t)40t`
or `q_(f)-q_(i)=(40t^(2))/(2)`
or `160-180=20t^(2)` or `T=2s`
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