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A parallel plate capacitor of capacitanc...

A parallel plate capacitor of capacitance `10 muF` is connected across a battery of emf 5 mV. Now, the space between the plates of the capacitors is filled with a deielectric material of dielectric constant K=5. Then, the charge that will flow through the battery till equilibrium is reached is

A

`250 muC`

B

`250 nC`

C

`200 nC`

D

`200 muC`

Text Solution

Verified by Experts

The correct Answer is:
C
The charge on capacitor before dielectric is
`q_(1)=CV=50xx10^(-9)C`
Final charge on capacitor after dielectric is `q_(2)=(KC)V=5xx50xx10^(-9)`
`=250xx10^(-9)C`
Charge flow from battery `triangleq=q_(2)-q_(1)=200nC`
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