Home
Class 12
PHYSICS
In the circuit shown, a capacitance 3muF...

In the circuit shown, a capacitance `3muF` is charged form a battery of emf `6V` with switch connected to terminal P. The switch is now connected to Q. This charges the `6muF` capacitor from the `3muF` one. What is the new potential difference across combination?

A

`1 V`

B

`2 V`

C

`4 V`

D

`6 V`

Text Solution

Verified by Experts

The correct Answer is:
B
b. Initially at switch position `Q`, by conservation of charge, the voltage `V` across the two capacitors is thus given by
`q=q_(1)+q_(2)=C_(1)V+C_(2)V=(C_(1)+C_(2))V`
or `18=(3+6)V`
or `V=(18//9)=2V`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS|Exercise Multiple Correct Answer type|109 Videos

  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS|Exercise Assertion and Reason Type|8 Videos

  • MECHANICAL PROPERTIES OF SOLIDS

    CENGAGE PHYSICS|Exercise Question Bank|4 Videos

  • MISCELLANEOUS VOLUME 5

    CENGAGE PHYSICS|Exercise Integer|12 Videos

Similar Questions

Explore conceptually related problems

In the circuit shown in figure, the charge stored on a capacitor of capacitance 3muF is

If charge on 5muF capacitor is 50muC , find the potential difference on 4muF and emf of battery.

A 10 muF capacitor is charged to a potential difference of 1000 V . The terminals of the charged capacitor are disconnected from the power supply and connected to the terminals of an uncharged 6 muF capacitor. What is the final potential difference across each capacitor ?

Two capacitors of capacitances 3 muF and 6 muF are charged to a potential of 12 V each. They are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each will be

A capacitor of capacitance 5 muF is charged to a potential difference of 10 volts and another capacitor of capacitance 9 muF is charged to a potential difference of 8 volts. Now these two capacitors are connected in such a manner that the positive plate of one is connected to the positive plate of other. Calculate the common potential difference across the two capacitors.

A capacitor of capacitance value 1 muF is charged to 30 V and the battery is then disconnected. If it is connected across a 2 muF capacotor, then the energy lost by the system is

A muF capacitor C_1 is charged to V_0 = 120 V . The charging battery is then removed and the capacitor is connected in parallel to an uncharged + 4muF capacitor C_2 . (a) what is the potential difference V across the combination? (b) what is the stored energy before and after the switch S is closed?

Two capacitors of capacitance 2muF and 4muF respectively are charged to a potential of 12 V. they are now connected to each other, with the positive plate of each joined to the negative plate of the other. The potential difference across each capacitor will be

The two capacitors in the circuit shown in figure are initially uncharged and then connected as shown and switch is closed. What is the potential difference across 3muF capacitor?

A capacitor of capacity 2 muF is charged to a potential difference of 12 V . It is then connected across an inductor of inductance 6 mu H . What is the current (in A ) in the circuit at a time when the potential difference across the capacitor is 6.0 V ?