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A positively charge sphere of radius r0 ...

A positively charge sphere of radius `r_0` carries a volume charge density `rho`. A spherical cavity of radius `r_0//2` is then scooped out and left empty. `C_1` is the center of the sphere and `C_2` that of the cavity. What is the direction and magnitude of the electric field at point B?

A

`(17rhor_0)/(54epsilon_0)` left

B

`(rhor_0)/(6epsilon_0)` left

C

`(17rhor_0)/(54epsilon_0)` right

D

`(rhor_0)/(6epsilon_0)` right

Text Solution

Verified by Experts

The correct Answer is:
A
a. Electric field on surface of a uniformly charged square is given by `(Q)/(4piepsilon_(0)R^(3))=(pR)/(3epsilon_(0))`
Electric field at outside point is given by
`E=(Q)/(4piepsilon_(0)r^(2))=(pR^(3))/(3piepsilon_(0)r^(2))`
`|vecE_(r)|=(pr_(0))/(3epsilon_(0))-(p((r_(0))/(2))^(3))/(3epsilon_(0)((3r_(0))/(2))^(2))=(17pr_(0))/(65epsilon_(0))`
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