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Two mutually perpendicular wire carry ch...

Two mutually perpendicular wire carry charge densities `lambda_1 and lambda_2`. The electric lines of force makes angle `alpha` with second wire, then `lambda_1//lambda_2` is

A

`tan^(2)alpha`

B

`cot^2 alpha`

C

`sin^2 alpha`

D

`cos ^2alpha`

Text Solution

Verified by Experts

The correct Answer is:
B
`E_(1)=(lambda_(1))/(2piepsilon_(0)x)` and `E_(1)=(lambda_(q))/(2piepsilon_(0)y)`
`(E_(1))/(E_(2))=((lambda_(1))/(lambda_(2)))((y)/(x))`
`(1)/(tanalpha)=((lambda_(1))/(lambda_(2)))tanalpha` or `(lambda_(1))/(lambda_(2))=cot^(2)alpha`
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