Home
Class 12
PHYSICS
A parallel plate capacitor of area A, pl...

A parallel plate capacitor of area A, plate separation d and capacitance C is filled with three different dielectric materials having dielectric constants `k_1`, `k_2` and `k_3` as shown. If a isngle dielectric material is to be used to have the same capacitance C in this capacitor, then its dielectic constant k is given by

A

`1/k = 1/k_1 + 1/k_2 + 1/(2k_3)`

B

`1/k = 1/(k_1+k_2) + 1/(2k_3)`

C

`k = (k_1k_2)/(k_1+k_2) + 2k_3`

D

`k = k_1 +k_2 + 2k_3`

Text Solution

Verified by Experts

The effective capacitance is given by
`(epsilon_(0)A)/(d)[(1)/(k_(1)+k_(2))+(1)/(2k_(3))]^(-4)`
The capacitance of a single capacitor will be `(epsilon_(0)A//d)k`.
`k=[(1)/((k_(1)+k_(2)))+(1)/(2k_(3))]^(-1)` or `(1)/(k)=(1)/((k_(1)+k_(2)))+(1)/(2k_(3))`
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS|Exercise Multiple Correct Answer type|109 Videos
  • MISCELLANEOUS VOLUME 3

    CENGAGE PHYSICS|Exercise Assertion and Reason Type|8 Videos
  • MECHANICAL PROPERTIES OF SOLIDS

    CENGAGE PHYSICS|Exercise Question Bank|4 Videos
  • MISCELLANEOUS VOLUME 5

    CENGAGE PHYSICS|Exercise Integer|12 Videos

Similar Questions

Explore conceptually related problems

A parallel plate capacitor of area A, plate separation d and capacitance C is filled with three different dielectric materials having dielectric constants k_1 k_2 and k_3 as shown in the following figure. If a single dielectric material is to be used to have the same capacitance C in this capacitor then its dielectric constant k is given by

A parallel -plate capacitor of area A , plate separation d and capacitance C is filled with four dielectric materials having dielectric constant k_(1), k_(2), k_(3) and k_(4) as shown in the figure below. If a single dielectric materical is to be used to have the same capacitance C in this capacitor, then its dielectric constant k is given by

A parallel plate capacitor of area A , plate separation d and capacitance C is filled with three different dielectric materials having dielectric constant K_(1),K_(2) and K_(3) as shown in fig. If a single dielectric material is to be used to have the same effective capacitance as the above combination then its dielectric constant K is given by :

A parallel plate capacitor with plate area A & plate separation d is filled with a dielectric material of dielectric constant given by K=K_(0)(1+alphax). . Calculate capacitance of system: (given alpha d ltlt 1) .

An air capacitor of capacitance C plate area A and plate separation d has been filled with three dielectrics of constant k_(1)=3 , k_(2)=6 and k_(3)=4 as shown in figure . What is the new capacitance ?