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Two equal negative charges -q are fixed ...

Two equal negative charges `-q` are fixed at points `(0, -a)` and `(0,a)` on y-axis. A poistive charge Q is released from rest at point `(2a, 0)` on the x-axis. The charge Q will

A

execute simple harmonic motion about the origin.

B

move to the origin and remain at rest

C

move to infinity

D

execute oscillatory but not simple harmonic motion

Text Solution

Verified by Experts

Let us consider the positive charge Q at any instant of time t at a distance x from the origin. It is under the influence of two forces, `F_(1)(=I)` and `F_(2)(=F)` on resolving these two forces, we find that F `sintheta` cancels out the resultant force is Since `F_(R)` is not propotional to x, the motion is not simple harmonic the charge Q will accelerate till the origin and gain velocity at the origin the net force is zero but due to momentum it will cross the origin and move towards left as it comes on the negative x-axis the force is again towards the origin
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