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When a galvanometer is shunted with a 4O...

When a galvanometer is shunted with a `4Omega` resistance the deflection is reduced to` 1//5`. If the galvanometer is further shunted with a `2Omega` wire the new deflection will be (assuming the main current remains the same)

A

`5//13` of the deflection when shunted with `4Omega` only

B

`8//13` of the deflection when shuntedwith `4Omega`only

C

`3//4` of the deflection when shunted with `4Omega` only

D

`3//13` of the deflection when shunted with `4Omega`only

Text Solution

Verified by Experts

The correct Answer is:
A
a. When only `4 Omega` resistance is shunted `i_g = i//5`
`G xx i//5 = 4 xx (4//5) or G = 16 Omega`
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