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In the petentiometer arrangemeter shown,...

In the petentiometer arrangemeter shown, the driving cell `A` has emf `epsilon` and internal resistance `r`. The emf of the cell `B` is `(epsilon)/(2)` and internal resistance `2r`. The petentiometer wire `CD` is `100 cm` long. If balance is obtained with length `CJ = l`, then

A

`l = 50cm`

B

`lgt50 cm`

C

`llt50cm`

D

Balanced cannot be obtained

Text Solution

Verified by Experts

The correct Answer is:
B
b. As potential gradient k in the potentiometer wire will be less than `(epsilon//100) (V cm^(-1))` because of the presence of r, so for the
battery of emf `epsilon//2`, the balance point l will be greater than 50 cm as shown.
`l = (epsilon//2)/(k(ltepsilon//100)) or lgt50 cm ` .
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