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In a practical wheat stone bridge circui...

In a practical wheat stone bridge circuit as shown, when one more resistance of `100 Omega` is connected in parallel with unknown resistance 'x', then ratio `l_1//l_2` become '2'`l_1` is balance length , AB is a uniform wire. Then value of 'x' must be :

A

`50 Omega`

B

`100 Omega`

C

`200 Omega`

D

`400 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
b. The Wheatstone bridge is in
balanced condition , so
`100/l_1 = ((100x)/(100+x))/(l_(2))`
`:. l_1/l_2 = 2 or x = 100 Omega`
.
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