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For the potentiometer arrangement shown ...

For the potentiometer arrangement shown in the figure, length of wire AB is 100 cm and its resistance is `9 Omega`. Find the length AC for which the galvanometer G will show zero deflection.

A

66.7 cm

B

60 cm

C

50 cm

D

33.3 cm

Text Solution

Verified by Experts

The correct Answer is:
A
a. Potential difference across AC is zero.
`5 - 2I = 0 E = 10V`
or `I = 2.5 A r = 1 Omega`
Let the resistance of part BC be
r. Applying KVL, we get
`10 + 5 - 2I - Ir - I = 0`
or ` 2.5 r = 7.5 or r = 3 Omega`
As resistance of part `AB = 9 Omega` ,
length `AC = 66.7 cm`
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