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In the circuit shwon in fig. switch S is...

In the circuit shwon in fig. switch S is closed at time t = 0. Let `I_1 and I_2` be the currents at any finite time t, then the ratio `I_1// I_2`

A

is constant

B

increases with increase in time t

C

decreases with increase in time t

D

first increases then decreases

Text Solution

Verified by Experts

The correct Answer is:
B
b. Here `I_1 = V/R e^(-t/(RC_1)) and I_2 = V/R e^(-t/(RC_2))`
`I_1/I_2 = (e^(-t/(RC_1)))/(e^(-t/(RC_2))) = e^(-t/R(1/C_1+1/C_2))`
`=e^((-t(C_1+C_2))/(RC_1C_2))`
Hence option (b) is correct.
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