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In the circuit shown, the cell is ideal ...

In the circuit shown, the cell is ideal with emf = `2V` . The resistance of the coil of the galvanometer `G` is `1 Omega`.

(i) No current flows in `G`
(ii) `0.2A` current flows in `G`
(iii) potential difference across `C_(1) is 1V`
(iv) Potential difference across `C_(2)` is `1.2V`

A

no current flows in G

B

0.2 A current flows in G

C

potential difference across `C_1 is 1 V`

D

potential difference across `C_2 is 1.2 V`.

Text Solution

Verified by Experts

The correct Answer is:
B, C, D
b., c., d. ,brgt Disregard capacitors and find the current through G. The
potential difference across each capacitor is then found from
the potential difference across the resistances in parallel with
them.
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