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In the circuit shown in figure...

In the circuit shown in figure

A

power supplied by the circuit is 200 W.

B

current flowing in the circuit is 5A

C

potential difference across `4Omega` resistance is equal to the potential difference across `6Omega` resistance

D

current in wire AB is zero.

Text Solution

Verified by Experts

The correct Answer is:
A, C
a., c.
Resistances `4 and 6 Omega` are short-circuited. Therefore, no
current will flow through these two resistances. Current
passing through the battery is `I = (20//2) = 10A`. This is also
the current passing in wire AB from B to A. Power supplied by
the battery is
`P = EI =(20)(10) = 200W`
Potential difference across the `4 Omega` resistance = potential
difference across the `6Omega` resistance = 0
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