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In the circuit shown in the figure ....

In the circuit shown in the figure
.

A

current passing through `2Omega` resistance is zero.

B

current passing through `4Omega` resistance is `5A`

C

current passing through `5Omega` resistance is 4A.

D

potential difference across `2Omega` resistance is zero.

Text Solution

Verified by Experts

The correct Answer is:
A, B, C, D

a., b., c., d.
`2Omega` resistance will be short-circuited as potential drop across
it is 0 also `4Omega` and `5Omega` are in parallel.
`1/R = (4+5)/(4xx5) = 9/20`
`I = 20/20 xx 9 = 9A rArr I_1 xx 4 = (9-I_1) xx 5`
`I_1 = 5A, I-I_1 = 4A` .
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