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Current through the battery in the circu...

Current through the battery in the circuit shown in the figure

A

immediately after the switch S is closed is `epsilon//R`

B

immediately after the switch S is closed is `epsilon //2R`.

C

after long time is `epsilon//2R`.

D

after long time is `3epsilon//4R`

Text Solution

Verified by Experts

The correct Answer is:
A, C
a., c.
Immediately after closing the switch, the capacitor will behave
like conducting wires, so all the resistances between B and G
will be short-circuited and current will flow through ABFEG.
Hence current `= epsilon//R`. After long time when the capacitors are
fully charged, current will go through ABDG. Hence current =
`epsilon//2R` .
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