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A parallel combination of 0.1 M Omega re...

A parallel combination of 0.1 `M Omega` resistor and a `10muF` capacitor is connected across a 1.5 V source of negligible resistance. The time (in sec) required for the capacitor to get charged upto 0.75 V is approximately

A

`oo`

B

`log_(e) 2`

C

`log_(10)2`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
b. For the capacitor to get charged up to
0.75 V, the charge on the plates should
be as follow.

`q=CE[1-e^(-t//RC)]`
or `0.75 xx 10^(-5) = 10^(-5) xx 1.5 [1-e^(-t/(10^5 xx 10^(-5)))]`
or `1/2 = [1-e^(-t)] or e^(-t) = 1/2`
Taking log on both sides, we get
`-t = -1n2 or t =0.693s`.
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