Find the lateral shift of a light ray while it passws through a parallel glass slab of thickness 10 cm places in air. The angle of incidence in air is `60^(@)` and the angle of refraction in glass is `45^(@)`.

Explanation

`d=(t sin(i-r))/(cos r)=(10sin(60^(@)-45^(@)))/(cos 45^(@))`
`=(10 sin 15^(@))/(cos 45^(@))=10sqrt2 sin15^(@)`.
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