An object is placed midway between a concave mirror of focal length f and a convex mirror of focal length f. The distance between the two mirrors is 6f. Trace the ray that is first incident on the concave mirror and then the convex mirror.

Explanation

Reflection from concave mirror
`u=3f_(1), f=-f`
`(1)/(v)+(1)/(u)=(1)/(f)rArr v=(3)/(2)f`
Now reflection from convex mirror
`u=(3f+(3)/(2)f)=+(9)/(2)f, f=-f`
Again using mirror formula, we get `v=(9f)/(11)`